Answer:
your friend did a work of 1717.34 J
Explanation:
The sum of the work made by your friend and you is equal the change in the kinetic energy, so:
Where is the work that you did, is the work that your friend did, m is the mass of the satellite and and are the final and initial speeds
Additionally the work that you did is equal to:
Where F and s are vectors. So, the vector s that said the displacement is calculated as:
s = <2.3, 2.6, -11.8> - <3.3, -1.6, 2.0>
s = <-1 , 4.2 , -13.8>
Therefore, is:
Then, replacing the values on initial equation and solving for , we get:
Finally, your friend did a work of 1717.34 J
Part a is simply mass*gravity. Tension=ma
Part b Tension= 50kg(10m/s+5.0m/s) = 750N
Answer:
(C) 16
Explanation:
Given:
The amplitude of first wave (s₁) = 20 mm
The amplitude of second wave (s₂) = 5 mm
Intensity of first wave = Iₓ
Intensity of second wave =
The intensity associated with a wave depends on the amplitude of the wave.
The intensity (I) is directly proportional to the square of the amplitude (s) of the wave and is expressed as:
Now, the intensities of the two waves are given as:
Dividing both the intensities, we get:
Therefore, the option (C) is correct.