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2 years ago

400-[200-{35+15-70(100/25)}] plz hurry

Mathematics

2 answers:

FinnZ [79.3K]2 years ago

5 0

Answer:

-30

Step-by-step explanation:

400-[200-{35+15-70(100/25)}]

400-[200-{35+15-70(4)}]

400-[200-{35+15-280}]

400-[200-{50-280}]

400-[200-{-230}]

400-[430]

-30

Rzqust [24]2 years ago

4 0

The answer is just -30 your welcome :)

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Write an equation for each description. a number increased by 10 is 114

laila [671]

x+10=114

114-10=x

x=104

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The notation __1____ reads the probability of Event B given that Event A has occurred. If Events A and B are independent, then t

telo118 [61]

P(B|A) (option B)

Doesn't affect (option A)

P(B|A) = P(B) (option A)

Explanation:

1) Conditional probabilities could be in the form P(A|B) or P(B|A)

P(B|A) is a notation that reads the probability of event B given that event A has occurred.

P(B|A) (option B)

2) Independent events do not affect the outcome of each other

For event A and B to be independent, the probability of event A occurring doesn't affect the the probability of event B occurring

Doesn't affect (option A)

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P(B|A) = P(B)

The ones that appeared in the option is P(B|A) = P(B) (option A)

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3 months ago

1. 1 +2r = 2. 12 = 18 - d 3. 5b + 10 = 30

seropon [69]

Answer:

1. r=anything

2. d=6

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Step-by-step explanation:

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2 years ago

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15. • Solve the simultaneous equations

tamaranim1 [39]

Answer:
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Explanation:
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2 years ago

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Answer:

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Where $\mu$ and $\sigma=0.08$

Since the distribution for X is normal then the we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error is given by:

$SE= \frac{0.08}{\sqrt{24}}= 0.0163$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,0.08)$

Where $\mu$ and $\sigma=0.08$

Since the distribution for X is normal then the we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error is given by:

$SE= \frac{0.08}{\sqrt{24}}= 0.0163$

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2 years ago