<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144
Solution:
Since it has to be between -13 and 89, letter d and b are not anymore considered to be the answer.
for a:
33-(-13)=46=d
43-33=10=d the value for this d is different from the two sequence,
89-43=46=d
they have different value for d, thus this is not the answer!
for c:
21-(-13)=34=d
55-21=34=d
89-55=34=d
they have the same value for d, thus the correct answer is </span><span> c. -13, 21, 55, 89</span>
Not sure but It should be -4/1
Pretty sure it’s “b= p/2 - a” which is the second answer
Answer:
330
Step-by-step explanation:
This is the "choose" formula.
The equation for the choose formula is this:
nCk = n! / k!(n-k)!
! = factorial.
Plug in our numbers:
11C4 = 11! / 4!(11-4)!
39916800 / 24(5040)
39916800 / 120960
330
Domain- {-2, 1, 0, 1, 2}
Range- {-2, 0, 2}
My domain is right but I don’t think my range is. I did learn this 4 years ago though so
