$6x ^2-7x+2=0\\ \\ a=6 , \ b = -7 , \ c=2 \\ \\\Delta = b^{2}-4ac = (-7)^{2}-4*6*2=49-48=1 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{7-\sqrt{1}}{2*6}=\frac{7-1}{12} =\frac{6}{12}= \frac{1}{ 2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{7+\sqrt{1}}{2*6}=\frac{7+1}{12} =\frac{8}{12}= \frac{2}{ 3}$

7 0

2 years ago

Evaluate the expression e^3

ella [17]

Answer:

The answer is 20.0855

Step-by-step explanation:

Calculate the approximate value

e³ = 20.0855

Hope this helps you

4 0

2 years ago

Read 2 more answers

How do you find the range of a function ?

Allushta [10]

By looking at the y values of a function or on a graph

8 0

2 years ago

SOLVING QUADRATIC EQUATIONS 2) Solve 2x2 - 5 = 27

Nimfa-mama [501]

Answer:

x = ±4

Step-by-step explanation:

Step 1: Write out quadratic

2x² - 5 = 27

Step 2: Add 5 to both sides

2x² = 32

Step 3: Divide both sides by 2

x² = 16

Step 4: Take the square root of both sides

x = ±4

∴ x can equal -4 or 4

7 0

2 years ago