Answer:
Volume of the frustum = ⅓πh(4R² - r²)
Step-by-step explanation:
We are to determine the volume of the frustum.
Find attached the diagram obtained from the given information.
Let height of small cone = h
height of the large cone = H
The height of a small cone is a quarter of the height of the large cone:
h = ¼×H
H = 4h
Volume of the frustum = volume of the large cone - volume of small cone
volume of the large cone = ⅓πR²H
= ⅓πR²(4h) = 4/3 ×π×R²h
volume of small cone = ⅓πr²h
Volume of the frustum = 4/3 ×π×R²h - ⅓πr²h
Volume of the frustum = ⅓(4π×R²h - πr²h)
Volume of the frustum = ⅓πh(4R² - r²)
Answer:
3 1/3 is already in the simplest form. It can be written as 0.230769 in decimal form (rounded to 6 decimal places).
Have an awesome day! :D
Answer:
The solution is in the attached file
Answer:
Step-by-step explanation:
Rate of change = (2-3.6)/(5-(-3)) = -1.6/8 = 0.2
A³ b² 4ab³
Rearrange order:
4 a³ a b² b³
Now add up the exponents from same base:
4 a³⁺¹ b²⁺³
4 a⁴ b⁵
Final answer: 4 a⁴ b⁵