Answer:
62.8 in
Step-by-step explanation:
formula to find surface area of cylinder = 2πrh + 2πr²
2 × 3.14 × 2 × 3 + 2 × 3.14 × 2²
37.68 + 25.12
62.8 in
4 1/7 = (4*100) +(1/7 of 100)= (400+ 14.28)= 414.28
The answer is 414.28
Answer:
The density of the bar of gold is 19.32 grams per cubic centimeter .
Step-by-step explanation:
Formula
As given
A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.
As 1 kilogram = 1000 gram
Than convert 13.949 kilograms into grams.
13.949 kilograms = 13.949 × 1000 grams
= 13949 grams
Mass = 13949 grams
Volume = 722 cubic centimeter
As put in the formula
Density = 19.32 grams per cubic centimeter (Approx)
Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .
Answer:
63
Step-by-step explanation:
Because, 100% of 70 would be 7. Now we have that number lets multiply it by 9 because of 90%. 9 x 7 = 63 first-graders