Answer:
c. Two sister chromatids did not separate into the proper daughter cells during anaphase.
Explanation:
The observed cell is undergoing mitosis which does not include separation of homologous chromosomes. During anaphase of mitosis, two sister chromatids of each chromosome separate from each other. They move to opposite poles. This results in equal distribution of two complete sets of chromosomes to each daughter cell.
However, the failure of two sister chromatids of a chromosome during anaphase would lead to the formation of two abnormal daughter cells. One of the daughter cells would have one extra chromosome (2n+1) while the other would lack one chromosome from the diploid set (2n-1).
Answer:
A the hole in the ozone layer is decreasing
B
Explanation:
Biochemical control and toxicity after intensity-modulated radiation therapy for prostate cancer. ... Biochemicalfailure was defined as PSA < post-treatment nadir+2.
