Answer:
both kinds of tickets are $5 each
Step-by-step explanation:
Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:
12s + 5c = 85 . . . . . revenue from the first day of sales
6s + 9c = 75 . . . . . . revenue from the second day of sales
Double the second equation and subtract the first to eliminate the s variable.
2(6s +9c) -(12s +5c) = 2(75) -(85)
13c = 65 . . . . . simplify
65/13 = c = 5 . . . . . divide by the coefficient of c
Substitute this value into either equation. Let's use the second one.
6s + 9·5 = 75
6s = 30 . . . . . . . subtract 45
30/6 = s = 5 . . . divide by the coefficient of s
The price of a senior ticket is $5; the price of a child ticket is $5.
Answer:
108 slices
Step-by-step explanation:
One pie is 6 slices so 6*18 is equal to 108
Answer:
14
Step-by-step explanation:
You can solve using PEMDAS:
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
3(2+5)-5(3)+8=?
3(7)-5(3)+8=?
No exponents
3(7)-5(3)+8=?
21-15+8=?
No division
21-15+8=?
21-7=?
21-7=14
3(2+5)-5(3)+8=14
The answer in order is b a c
Answer:
193.53 miles
Step-by-step explanation:
Please see the diagram for understanding of how the angles were derived,
Applying Alternate Angles, ABO =77 degrees
The bearing from B to C is 192=180+12 degrees
Subtracting 12 from 77, we obtain the angle at B as 65 degrees.
We want to determine the boat's distance from its starting point.
In the diagram, this is the line AC.
Applying Law of Cosines:
The distance of the boat from its starting point is 193.53 miles (correct to 2 decimal places).
