Step-by-step explanation:
Here, f(x) is the given polynomial.
By remainder Theorem,
When divided by (3x-1),
f(1/3) = -3........(1)
When divided by (x+1),
f(-1) = -7.........(2)
<em>Another</em><em> </em><em>polynomial</em><em> </em><em>is</em><em> </em><em>3</em><em>x</em><em>²</em><em>+</em><em>2</em><em>x</em><em>-</em><em>1</em>
Solving,
3x²+2x-1
= 3x²+3x-x-1
=3x(x+1)-(x+1)
=(3x-1)(x+1)
So
f(x) = (3x-1)(x+1)Qx + (ax+b)
For f(-1),
-7 = -a+b
b= a-7
For f(1/3),
-3 = a/3+b
or, -3 = a/3+a-7
or, 4×3 = 4a
or a = 3
Also, b = 3-7 =-4
Hence, remainder is (3x-4)
The arithmetic sequence with the given condition is determined recursively by
So we have
and so on with the general pattern
This means the 72nd term in the sequence is
so the answer is B.
Answer:
The answer is 445,446
Step-by-step explanation:
have a great day everyone :)
Answer:
Product (multiplication) of 2a+3b-c and 2a+3b-c is −2ac+2a+6b−c.
Explanation:
2a+3b−c(2)a+3b−c
= 2a+3b+−2ac+3b+−c
Combine Like Terms:
= 2a+3b+−2ac+3b+−c
= (−2ac)+(2a)+(3b+3b)+(−c)
= −2ac+2a+6b+−c
Answer:
DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD
Step-by-step explanation: