Answer:
actually no triangle exists with the given angle measure. more than ONE unique triangle exists with the given angle measures. exactly one unique triangle exists with the given angle measures
Answer:
The answer is 9.
Step-by-step explanation:
PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction)
3x10+15-6^2
3x10+15-36
30+15-36
45-36
9
Aruthmetic sequene is
an=a1+(n-1)d
where d=common difference between terms
adds 6 every time
d=6
first term is 8
a1=8
8+6(n-1)
distribute
8+6n-6
8-6+6n
2+6n is answer
Answer:
In a short terms, if you have geometric sequences are most likely(99% sure) to be exponential functions because aromatic functions are the opposite of exponential. Aromatic function are used for linear equation, graphs, and functions while exponential functions will be used for exponential equations, graphs, and functions. So yes, all geometric sequences are in fact exponential functions.
Hope this is helpful.
Answer:
Step-by-step explanation:
1.
Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.
2.
Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.
3.
Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following (). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,
4.
The same method used to solve problem (3) can be applied to this problem.