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2 years ago

12

Runner a averages 5 mph and run it B rat averages 6 mph these rates how much longer does it take runner A then runner be to run

15 miles

1 answer:

Kipish [7]2 years ago

8 0

Takes runner A 18 more minutes

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Factor y 2 + 5y + 6.<br> (y + 1)(y + 6)<br> (y + 2)(y + 3)<br> (y + 2)(y + 4)

serg [7]

<span>y^2 + 5y + 6
=</span><span>(y + 2)(y + 3)

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5 0

2 years ago

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Write the first 5 terms of the sequence 90 - 8n

Blababa [14]

I hope this helps you

90-8.5

90-40

50

4 0

2 years ago

Nadia buys boxes of crackers that each has the same cost c. She represents the cost of 6 boxes of cheese crackers, 5 boxes of po

snow_lady [41]

I believe the answer is b because u need to combine like terms and 6c+2c+5c is 13c.

6 0

1 year ago

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The weight distribution of parcels sent in a certain manner is normal with mean value 17 lb and standard deviation 3.3 lb. The p

Yakvenalex [24]

Answer: The value of c would be 26.514 lb.

Step-by-step explanation:

Since we have given that

Mean = 17 lb

Standard deviation = 3.3 lb

At 99% level of significance, z = 2.58

So, it becomes,

$Z=\dfrac{X-\mu}{\sigma}\\\\2.58=\dfrac{X-17}{3.3}\\\\2.58\times 3.3=X-17\\\\8.514+17=X\\\\X=25.514$

So, the weight c would be

$c=25.514+1\\\\c=26.514$

Hence, the value of c would be 26.514 lb.

7 0

2 years ago

Can someone help me with this question

Tasya [4]

I’m pretty sure you add 78+55= 133
180-133=47
so 9x+2=47
subtract 2 from 47 and itself
so 9x=45
divide 9 and 45 by 9
so x=5

8 0

2 years ago