To solve this problem, set up and solve a system of equations. The variables b and m will represent a bread loaf and milk jug, respectively:
I would solve using substitution. Take one of the equations and set it equal to one of the variables, for example:
Now, plug this into the other equation for m and solve for b:
We now know that a loaf of bread costs $2.50. Plug this value in for b in the first equation and solve for m:
One jug of milk costs $1.50 and one loaf of bread costs $2.50.
Either would work, but substitution looks a bit easier.
The graph for these two is shown below.
I just put the equations in just as they are written. They did not have to be changed in any way. DESMOS is a wonderful program. Very powerful.
The blue line is 2x + y = - 6
The red line is y = x + 3
The best way to solve this other than a graph is to use substitution. Put the red graph into the blue one.
2x + y = - 6
2x +(x + 3) = - 6
2x + x + 3 = - 6
3x + 3 = - 6 Subtract 3 from both sides.
3x = - 6 - 3
3x = - 9
x = -9/3
x = -3
Now go back and solve for y
y = x + 3
y = -3 + 3
y = 0
Answer
The solution point is (-3,0) just what the graph shows.
Answer:
If you have given an equation, you see the x and y in it. Just taking second equation and think any common factor between x's variable. With common factor, multiply both and you will find the value of y and put it in any equation, you will find the value of X.
Step-by-step explanation:
Answer: Stratified
Step-by-step explanation:
Answer:
Theorem for alternate exterior angles.
Step-by-step explanation:
From the figure attached,
Two lines GN and FH are the parallel lines and a transversal JM is intersecting these lines at two distinct points.
Different pair of angles formed are between these parallel lines,
∠6 ≅ ∠10 [Corresponding angles]
∠8 ≅ ∠10 [Interior alternate angles]
∠6 ≅ ∠13 [Exterior alternate angles]
Therefore, theorem for alternate exterior angles justifies that ∠6 ≅ ∠13.
