Answer:
Month 1: she rode 33.3 miles
Month 2: she rode 16.65 miles
Month 3: She rode 133.2 miles
meaning in Month 3 she rode about 4 times more then month one and about 8 times more then she did in month 2
Step-by-step explanation:
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4 > 6*t
Number t refers to an unknown. In this case, t can only be 0, because 6*0 = 0, and 4 > 0 or four is greater than 0.
Preliminary Problem
Givens
Miles = m = 392 miles
Gallons = G = 14 gallons
Miles per gallon = mpg
Formula
miles = miles per gallon * number of gallons.
Solve
392 = mpg * 14 Divide by 14
392 / 14 = mpg
28 = mpg which is really quite good. Our vehicle gets 44 mpg but it's a 4 cylinder. It's meant to get that kind of milage.
Part A
Let x = the number of gallons used
Let y = the number of miles driven
y = k*x
Part B
y = k* x
k =28 mpg
11700 = 28*x
11700 /28 = x
x = 417.86
If this is incorrect please put some more facts in. The question does not seem complete.
5c^5 + 60c^4 + 180c^3
find the GCF, 5c³
5c³(5c^5 + 60c^4 + 180c^3/ 5c^3)
5c³(c² + 12c + 36)
5c³(c² + 2(c)(6) + 6²)
5c³(c + 6)² <<< the answer.
hope this helps, God bless!
