Answer:
7.
A.) -⅔
B.) 3/-2
Step-by-step explanation:
from 1 to -1 you have to go down 2
from 2 to -1 you have to go down 3
therefore your slope is -⅔
from 3 to 6 you go up by 3
from 1 to -1 you go down by 2
therefore your slope is 3/-2
if you add 55% and 45% the total is 100% so 45/100 are girls. 35% of the girls scored and A so 35/45 is the probability that it is a girl chosen or 7/9. the probability is 7 out of 9.
Answer:
144
Step-by-step explanation:
Put the number where the variable is and do the arithmetic.
9p^2 = 9·4^2 = 9·16
9p^2 = 144 . . . . when p=4
<span>149 times 235 is equal to </span>35,015.
Answer:
H0: μd=0 Ha: μd≠0
t= 0.07607
On the basis of this we conclude that the mean weight differs between the two balances.
Step-by-step explanation:
The null and alternative hypotheses as
H0: μd=0 Ha: μd≠0
Significance level is set at ∝= 0.05
The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571
The test statistic under H0 is
t = d/ sd/ √n
Which has t distribution with n-1 degrees of freedom
Specimen A B d = a - b d²
1 13.76 13.74 0.02 0.004
2 12.47 12.45 0.02 0.004
3 10.09 10.08 0.01 0.001
4 8.91 8.92 -0.01 0.001
5 13.57 13.54 0.03 0.009
<u>6 12.74 12.75 -0.01 0.001</u>
<u>∑ 0.06 0.0173</u>
d`= ∑d/n= 0.006/6= 0.001
sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882
sd= 0.05368
t= 0.001/ 0.05368/ √6
t= 0.18629/2.449
t= 0.07607
Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.