2.87mL of 2.5 M K2SO4 are required to obtain 1.25 grams of the compound.
<h3>HOW TO CALCULATE VOLUME?</h3>
The volume of a substance can be calculated by dividing the number of moles of the substance by its molarity. That is;
volume = no. of moles ÷ molarity
According to this question, 2.5M K2SO4 are required to obtain 1.25 grams of the compound. The volume can be calculated as follows:
Molar mass of K2SO4 = 174.26 g/mol
moles of K2SO4 = 1.25g ÷ 174.26g/mol
moles of K2SO4 = 0.00717moles
Volume = 0.00717moles ÷ 2.5
Volume = 0.00287 L = 2.87mL.
Therefore, 2.87mL of 2.5 M K2SO4 are required to obtain 1.25 grams of the compound.
Learn more about volume at: brainly.com/question/1578538
Answer:
The number of moles of salt in one tablespoon is = <u>0.11 mole</u>
<u>Grams </u>cancel each other.
Explanation:
<u>Moles</u> : It is the unit of quantity . It is the mass of the substance present in exactly 12g of C-12.
<u>Moles Calculation:</u>
Given mass = 6.37 gram
Molar mass = 58.5 g/mol
= 0.1088
= 0.11 mole
<u>Units calculation</u>
<u>g ang g cancels each other </u>
moles = moles
<u>Hence unit = gram (g ) cancel each other.</u>
Answer:
MnO4 + 4 H2C2O4 = Mn + 8 CO2 + 4 H2O
Answer:
C
Explanation:
Calculate the number of moles of Al2O3 that are produced when 15 mol of Fe is produced
in the following reaction.
C) 45 mol