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2 years ago

Directions: Foil the following if the answer is not standard form then standardize it.

Mathematics

2 answers:

larisa86 [58]2 years ago

7 0

The answer to your question is
4x^2+11x-20
(the “^2” is the tiny 2 lol)

Hatshy [7]2 years ago

4 0

The answer to your question is 4x^2+11x-20

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Reflect quadrilateral SQRT over the y-axis. Then translate the new quadrilateral 3 units to the right. What are the coordinates

wel

Answer: S(-5;3) Q(-2;2) R(-3;-2) T(-6;-1)

When reflected over the y-axis, their x values will change sign

S(5;3) Q(2;2) R(3;-2) T(6;-1)

Translate 3 units to the right, their x values will increase by 3

S(8;3) Q(5;2) R(6;-2) T(9;-1)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The data show the average monthly temperatures for two cities over a 6-month period. City 1: {20, 24, 40, 63, 76, 89} City 2: {4

Mrac [35]

Answer:

The MAD of city 2 is less than the MAD for city 1, which means the average monthly temperature of city 2 vary less than the average monthly temperatures for City 1.

Step-by-step explanation:

For comparing the mean absolute deviations of both data sets we have to calculate the mean absolute deviation for both data sets first,

So for city 1:

$Mean = x1 = \frac{20+24+40+63+76+89}{6}$

$x1 = \frac{312}{6}$

$x1 = 52$

Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored as the deviation is the distance of value from the mean and it cannot be negative. For this purpose absolute is used)

$20-52 = -32=32\\24-52=-28=28\\40-52=-12=12\\63-52=11\\76-52=24\\89-52=37$

The deviations will be added then. $Mean Absolute Deviation = \frac{32+28+12+11+24+37}{6} \\=\frac{144}{6}\\=24$

So the mean absolute deviation for city 1 is 24 ..

For city 2:

$Mean = x2 = \frac{41+50+58+62+72+83}{6}$

$x2 = \frac{366}{6}$

$x2 = 61$

Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored)

$41-61=-20=20\\50-61=-11=11\\58-61=-3=3\\62-61=1\\72-61=11\\83-61=22$

The deviations will be added then. $Mean Absolute Deviation = \frac{20+11+3+1+11+22}{6} \\=\frac{68}{6}\\=11.33$

So the MAD for city 2 is 11.33 ..

So,

The MAD of city 2 is less than the MAD for city 1, which means the average monthly temperature of city 2 vary less than the average monthly temperatures for City 1.

3 0

2 years ago

Read 2 more answers

(5.2x10^4)+(3.6x10^3)

yawa3891 [41]

Answer:

55600

Step-by-step explanation:

5.56*10^4

5 0

2 years ago

Improper fraction for 5 9/13