.
Oxygen-16 is the atom in question.
- Atomic number: 8.
- Mass number: 16.
<h3>Explanation</h3>
The superscript of the ion says "2-". That means that the ion here carries a charge of -2.
- The charge is negative, meaning that there are more electrons (which are negative) than protons (which are positive) in that ion.
- The size of the charge is 2. There are two more electrons than protons in that ion.
There are 10 electrons in total in that ion. There are two more electrons than protons. That means that there are 10 - 2 = 8 protons in that ion.
The atomic number of an atom is the same as its number of protons. The atomic number of X is 8.
The atomic number determines the element. Atomic number 8 is oxygen. Thus element X is oxygen.
Mass number is the sum of number of protons and neutrons in an atom. 8 + 8 = 16 for this atom.
The last intermediate in citric acid cycle is Oxaloacetic acid.
<h3>What is Citric Acid Cycle?</h3>
Organic molecule HOC(CO2H)(CH2CO2H)2 is the chemical formula for citric acid. It is a weak organic acid that is colorless. Citrus fruits naturally contain it. It is a biochemical intermediary in the citric acid cycle, which is a component of all aerobic organisms' metabolism.
Every year, more than two million tons of citric acid are produced. It is frequently used as a flavoring, an acidifier, and a chelating agent.
Citrates, which include salts, esters, and the polyatomic anion present in solution, are derivatives of citric acid. Trisodium citrate is an example of the former; triethyl citrate is an example of an ester.
Learn more about citric acid with the help of the given link:
brainly.com/question/15582668
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The brackets are indicating a(n) __Hydrogen___ bond.
1. Hydrogen
When heat energy is supplied to a material it can raise the temperature of mass of the material.
Specific heat is the amount of energy required by 1 g of material to raise the temperature by 1 °C.
equation is
H = mcΔt
H - heat energy
m - mass of material
c - specific heat of the material
Δt - change in temperature
substituting the values in the equation
120 J = 10 g x c x 5 °C
c = 2.4 Jg⁻¹°C⁻¹
Test tubes, flasks, bunsen burners, random chemical equations
