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2 years ago

7

Please help im timed with 3 mins left! will mark branliest

2 answers:

Serjik [45]2 years ago

7 0

It’s D hope this helps with your assignment

ad-work [718]2 years ago

3 0

Answer: ITS D

Step-by-step explanation:

Imma just answer real quikc since its timed if u want explanation just ask

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The ratio table below shows the relationship between the weight of apples purchased and the total cost of the apples.

Flauer [41]

When the weight of apples is increased by a factor of 4, total cost increases by 8.

<h3>What is the increase in total cost?</h3>

The first step is to determine the relationship between the weight of apples and their total cost.

Relationship between weight and total cost = $2 / 1 = $2

Increase in total cost = $2 x 4 = $8

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1 year ago

Twenty-four players divided into three teams?

avanturin [10]

24÷3=8

There will be eight players on each team.

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2 years ago

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Which is the solution set of the inequality 15y-9<36

m_a_m_a [10]

15y - 9 <36.
Add 9 to each side.

15y- 9 (+9) < 36 + 9.
15y < 45.
y < 3.
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2 years ago

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The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

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2 years ago

An amount of money b divided by 20 is $7. What is the amount?

olga2289 [7]

The amount of money, b, is $140.

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1 year ago

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