XY is formed by X(-9,-7) and Y (-3,5 is line j is the perpendicular bisector of XY

The Hiking Club is taking another trip. The hike leader's watch shows that they gained 296 feet in altitude from their starting

algol13

Answer: altitude at starting point is -11ft or 11ft below sea level
Step-by-step explanation:
Equation for this situation will be
A = Ag - 11
A = actual altitude
Ag = altitude gained.
At starting point, altitude gained is zero, therefore;
A = 0 - 11
A = -11ft

7 0

2 years ago

200x50 mathematics problem

Neporo4naja [7]

200*50=10,000.
2*5=10
20*50=1000
200*50=10000

8 0

3 years ago

Read 2 more answers

Show that if X is a geometric random variable with parameter p, then

Lubov Fominskaja [6]

Answer:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

In order to find the expected value E(1/X) we need to find this sum:

$E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}$

Lets consider the following series:

$\sum_{k=1}^{\infty} b^{k-1}$

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

$\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}$ (a)

On the last step we assume that $0\leq r\leq b$ and $\sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}$ , then the integral on the left part of equation (a) would be 1. And we have: