Answer: He can buy 5 loaves of bread.
After buying 5 loaves 15 p will be left.
Step-by-step explanation:
Given, In the supermarket a loaf of bread costs 37p .
To find: How many loaves can David buy with a coin?
Since
Then,
Number of loaves he can buy = (Amount he has) ÷ (Cost of a loaf of bread)
= 200 p ÷ 37 p
i.e. he can buy 5 loaves of bread and 15 p will be left.
Hence, He can buy 5 loaves of bread.
After buying 5 loaves 15 p will be left.
Answer:
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Answer:
mM = 113 and mN = 61
Step-by-step explanation:
In a Cyclic quadrilateral, the rule states that:
The sum opposite interior angles is equal to 180°
In the above diagram, we have cyclic quadrilateral KLMN
According to the rule stated above:
Angle K is Opposite to Angle M
So, Angle K + Angle M = 180°
Angle K = 67°
67° + Angle M = 180°
Angle M = 180° - 67°
Angle M = 113°
Angle L is Opposite to Angle N
so Angle L + Angle N = 180°
Angle L is given as = 119°
119° + Angle N = 180°
Angle N = 180° - 119°
Angle N = 61°
Therefore, Angle M = 113° and Angle N = 61°
The numbers are: 36 and 11 .
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Explanation:
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Let us represent the TWO (2) numbers with the variables;
"x" and "y" .
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x + y = 47 .
y − x = 25.
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Since: " y − x = 25 " ;
Solve for "y" in terms of "x" ;
y − x = 25 ;
Add "x" to each side of the equation:
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y − x + x = 25 + x ;
to get:
y = 25 + x .
Now, since:
x + y = 47 ;
Plug in "(25 + x)" as a substitution for "y"; to solve for "x" :
x + (25 + x) = 47 ;
x + 25 + x + 47 ;
2x + 25 = 47 ;
Subtract "25" from each side of the equation:
2x + 25 − 25 = 47 − 25 ;
2x = 22 ;
Divide EACH SIDE of the equation by "2" ;
to isolate "x" on one side of the equation; and to solve for "x" ;
2x / 2 = 22 / 2 ;
x = 11 ;
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x + y = 47<span> ;
</span>Plug in "11" for "x" into the equation ; to solve for "y" ;
11 + y = 47 ;
Subtract "11" from EACH SIDE of the equation;
to isolate "y" on one side of the equation; and to solve for "y" ;
11 + y − 11 = 47 − 11 ;
y = 36 .
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So: x = 11 , y = 36 ;
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Let us check our work:
y − x = 25 ;
36 − 11 =? 25 ? Yes!
x + y = 47 ;
36 + 11 =? 47 ? Yes!
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The numbers are: 36 and 11 .
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