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2 years ago

Please help me to answer this question.i have to submit tomorrow.

Chemistry

1 answer:

ratelena [41]2 years ago

4 0

Answer:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

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Scientists have collected the following data regarding rock ages along a mid-ocean ridge.

ivanzaharov [21]

The statement is supported by the data, is that the youngest rocks on the seafloor were at the mid-ocean ridge.

<h3>What is the evidence regarding the age of the rocks?</h3>

The data collected by scientists regarding rock ages along a mid-ocean ridge seafloor with mid-ocean ridge showing age of rock increasing the further from the ridge.

From the data, they found that the youngest rocks on the seafloor were at the mid-ocean ridge and the rocks get older with distance from the ridge crest.

Thus, the statement is supported by the data, is that the youngest rocks on the seafloor were at the mid-ocean ridge.

Learn more about age of rocks here: brainly.com/question/23546028

#SPJ1

4 0

1 year ago

How many sulfur atoms are in 0.45 mol BaSO4??

Lemur [1.5K]

$(0.45 mol BaSO_{4})*(\frac{6.022*10^23 molecules}{mol})*(\frac{1 atom S}{1 molecule BaSO_{4}}) = 2.7*10^{23}$

4 0

2 years ago

Read 2 more answers

Calculate the wavelength for the transition from n = 4 to n = 2, and state the name given to the spectroscopic series to which t

finlep [7]

Answer:

The wavelength for the transition from n = 4 to n = 2 is 486nm and the name name given to the spectroscopic series belongs to The Balmer series.

Explanation

lets calculate -

Rydberg equation- $\frac{1}{\pi } =R(\frac{1}{n_1^2} -\frac{1}{n_2^2})$

where , $\pi$ is wavelength , R is Rydberg constant ( $1.097\times10^7$ ), $n_1$ and $n_2$ are the quantum numbers of the energy levels. (where $n_1=2 , n_2=4$ )

Now putting the given values in the equation,

$\frac{1}{\pi }=1.097\times10^7\times(\frac{1}{2^2} -\frac{1}{4^2} )$ $=2056875m^-^1$

Wavelength $\pi =\frac{1}{2056875}$

= $4.86\times10^-^7$ = 486nm

 Therefore , the wavelength is 486nm and it belongs to The Balmer series.

8 0

2 years ago

Calculate the final Celsius temperature when 634 L at 21 °C is compressed to 307 L.

Illusion [34]

Answer:

- 130.64°C.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have two different values of V and T:

V₁T₂ = V₂T₁

V₁ = 634.0 L, T₁ = 21.0°C + 273 = 294.0 K.

V₂ = 307.0 L, T₂ = ??? K.

∴ T₂ = V₂T₁/V₁ = (307.0 L)(294.0 K)/(634.0 L) = 142.36 K.

∴ T₂(°C) = 142.36 K - 273 = - 130.64°C.

5 0

2 years ago

KHP is a monoprotic acid which provides one H+ ion. How would your results be affected if a diprotic acid (such as sulfuric acid

kari74 [83]

Explanation:

In a diprotic acid, 2 moles of H+ ions is released. Therefore, number of moles of H+ in a diprotic acid = 2 × number of moles of H+ of monoprotic acid.

Equation of the reaction

2NaOH + H2SO4 --> Na2SO4 + 2H2O

Number of moles of H2SO4 = molar concentration × volume

= 0.75 × 0.0105

= 0.007875 moles.

By stoichiometry, since 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, number of moles of NaOH = 2 × 0.007875

= 0.01575 moles.

Molar concentration of NaOH = number of moles ÷ volume

= 0.01575 ÷ 0.0175

= 0.9 M of NaOH.

7 0

2 years ago

Please help me to answer this question.i have to submit tomorrow.​

Please help me to answer this question.i have to submit tomorrow.