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2 years ago

Select the numbers that make the inquality true. selct all that apply. m > 0

Mathematics

1 answer:

sineoko [7]2 years ago

5 0

Answer:

1, 2, 3

Step-by-step explanation:

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At the Canada Open Tennis Championship, a statistician keeps track of every serve that a player hits during the tournament. The

kondaur [170]

Answer:

a) 54 mph to 144 mph

Step-by-step explanation:

We don't know the shape of the distribution, so we use Chebyshev's Theorem to solve this question. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

At least eight-ninths of the player's serves.

8/9 is approximately 89%

Mean: 99, standard deviation: 15

99 - 3*15 = 54

99 + 3*15 = 144

So the correct answer is:

a) 54 mph to 144 mph

8 0

2 years ago

400 meters to 350 meters

OleMash [197]

Minus 150 meters pepega I don’t quite understand the question but that is one way to get from 400 to 350 meters.

8 0

2 years ago

A middle school took all of its 6th grade students on a field trip to see a symphony at

butalik [34]

Answer:

49%

Step-by-step explanation:

to get the percentage you put the number of occupied seats over total number of seats and multiply it by 100 over 1

4 0

2 years ago

Multiple Choice: Please select the best answer.

PSYCHO15rus [73]

D. 171

-

Explanation:

4(2+5)^2 - 5^2

4 x 7^2 - 5^2

4 x 49 - 25

196 - 25

171

Answer: D. 171

7 0

2 years ago

In triangle abc, cos A= -0.6. Find A and Tan A

Tresset [83]

Answer:

Part 1) $A=126.87^o$

Part 2) $tan(A)=-\frac{4}{3}$

Step-by-step explanation:

we have

$cos(A)=-0.6$

The cos(A) is negative, that means that the angle A in the triangle ABC is an obtuse angle and the value of the sin(A) is positive

The angle A lie on the II Quadrant

step 1

Find the measure of angle A

$cos(A)=-0.6$

using a calculator

$A=cos^{-1}(-0.6)=126.87^o$

step 2

Find the sin(A)

we know that

$sin^2(A)+cos^2(A)=1$

substitute the value of cos(A)

$sin^2(A)+(-0.6)^2=1$

$sin^2(A)=1-0.36$

$sin^2(A)=0.64$

$sin(A)=0.8$

step 3

Find tan(A)

we know that

$tan(A)=\frac{sin(A)}{cos(A)}$

substitute the values

$tan(A)=\frac{0.8}{-0.6}$

Simplify

$tan(A)=-\frac{4}{3}$

5 0

2 years ago