B. Move from their ground states up to excited states
:)
Well, you should TAKE COVER UNDER A STUDY DESK, TABLE OR AGAINST AN INSIDE WALL. Which is C. This is because, doing this protects you from the falling objects. If you do A or B, you will probably get crushed by falling objects because you are exposed. Hope I helped.
Answer:
F = -6472.9 N
F= -6.47 kN
Explanation:
First of all you have to convert the data to SI units
so for the velocity you have :
Vi = 43km/h *(1000m/1km)*(1h/3600s) ---> using conversion factors
Vi= 11.9444 m/s
dX : distance the passanger moves
dX = 54cm*(1m/100cm) --> using conversion factors
dX = 0.54 m
Now to calculate the force we are going to use the sum of focers equals to mass for acceleration:
Sum F = m*a
We have to find a so we are going to use the velocity's formula as follows to solve a:
Vf ^2 = Vi^2 +2*a*dX
Vf=0 --> the passenger does not move after the airbag inflates.
a= -(Vi^2)/(2*dX)
you solve de acceleration with the data you hae and you will find
a = -132.1 m/ s^2
Now you can solve the Sum F equation
Sum F = 49 Kg * (-132.1 m/s^2)
F = -6472.9 N
F= -6.47 kN
Answer:
Explanation:
Given that,
A vector A has x component to be 2.7cm and y component to be 2.25cm
Then,
A = 2.7•i + 2.25•j
A vector B has x component of 0.30cm and y component of 1.75cm
B = 0.3•i + 1.75•j
So, we want to find A+B
Addition of vectors
Generally
(a•i + b•j) + (c•i + d•j) = (a+c)•i +(b+d)•j
Vectors are added component wise.
So,
A + B = (2.7•i + 2.25•j) + (0.3•i + 1.75•j)
A + B = (2.7 + 0.3)•i + (2.25 + 1.75)•j
A + B = 3•i + 4•j
We can also find it magnitude and direction
Generally,
A = a•i + b•j
|A| = √(a²+b²)
<A = arctan(b/a)
So,
|A+B| = √(3²+4²) = √9+16 = √25
|A+B| = 5
And it's direction
< = arctan(y/x)
< = arctan(4/3)
< = 53.13°
