MAg*cAg*(T1-T)=ρalc*Valc*calc*(T-T2)
mAg=?(g)
cAg=0.24J/gC
T1=95
T=23.5
Valc=25.6ml
ρalc=0.7893g/ml
T2=19.27
use wollframalpha or calculator
Let us say that R is the major enantiomer, while
S is the minor enantiomer, therefore the formula for enantiomeric excess (ee)
is:
ee = (R – S) * 100%
Let us further say that the fraction of R is x (R
= x), and therefore fraction of S is 1 – x (S = 1 – x), therefore:
75 = (x – (1 – x)) * 100
75 = 100 x – 100 + 100 x
200 x = 175
x = 0.875
Summary of answers:
R = major enantiomer = 0.875 or 87.5%
<span>S = minor enantiomer = (1 – 0.875) = 0.125 or
12.5%</span>
The time take for the train to travel 950 Km is 7.92 h
<h3>What is speed? </h3>
Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
With the above formula, we can determine the time. Details below:
<h3>How to determine the time</h3>
The time taken for the train t travel 950 Km can be obtained as follow:
- Speed = 120 Km/h
- Distance = 950 Km
- Time =?
Speed = distance / time
120= 950 / time
Cross multiply
120 × time = 950
Divide both side by 120
Time = 950 / 120
Time = 7.92 h
Learn more about speed:
brainly.com/question/680492
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