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2 years ago

Help on this question

Mathematics

1 answer:

malfutka [58]2 years ago

6 0

Step-by-step explanation:

always write what you know

circumference

U = 2 x pi x r

r = d/2

U = 39.25

rearrange and solve for r

U / (2 x pi) = r

solve for diameter

2r = d

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Yanka [14]

Answer:

TQ = 83.5

Step-by-step explanation:

11/54 = 17/TQ

11TQ = 918

TQ = 918/11 = 83.45

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2 years ago

A Scale model of a building is 12 inches tall. The actual building is 160 feet tall. What is the scale factor of the model write

zhannawk [14.2K]

Answer:

133/10

Step-by-step explanation:

divide 160 and 12 then simplify your answer

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2 years ago

You plan to set up an endowment at your alma mater that will fund $209,000 of scholarships each year indefinitely. If the princi

Leto [7]

Answer:

$199,047.62

Step-by-step explanation:

PV = X(1+i)^nm

X=$209000

i=5% = 0.05

n=1

m=1

Pv=$209000(1+0.05)^-1x1

Pv=$209000(1.05)^-1

Pv=$209000(1/1.05)

Pv=$209000/1.05

Pv=$199,047.62

$199,047.62 is needed to be donated for investment at 5.0% compounded annually rate for a year so as to get $209,000 at end of the year for the purpose of funding the scholarship.

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2 years ago

The table below shows some inputs and outputs of the invertible function f with domain all real numbers.

Ratling [72]

Answer:

${f}^{ - 1} (f(93)) = 93$

$f(f(7)) = - 15$

Step-by-step explanation:

A function and its inverse has the following properties

${f}^{ - 1} (f(x)) = x$

This implies that;

${f}^{ - 1} (f(93)) = 93$

From the table,

$f(7) = - 6$

This means that:

$f(f(7)) = f( - 6)$

$f(f(7)) = - 15$

Note that: f(7) means the value of f(x) when x=7.

From the table f(x)=-6 when x=7.

That is why f(7)=-6.

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2 years ago

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Archy [21]

$(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-6)}}} \implies \cfrac{2 +1}{-4 +6} \implies \cfrac{ 3 }{ 2 }$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{(-6)}) \implies {\large \begin{array}{llll} y +1= \cfrac{3}{2} (x +6) \end{array}}$

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6 months ago