This is essentially asking how many different ways to partition 6 into 3 segments.
I am assuming "no ball in a box" is not allowed.
6 can be partitioned as
(4,1,1), (3,2,1), and (2,2,2)
So, calculate each partition, we get
(6 choose 4) + (6 choose 3)*(3 choose 2) + (6 choose 2) * (4 choose 2)
= 15 + 20*3 + 15*6
=165
Answer:
C) SSS
Step-by-step explanation:
<em>SSS</em> stands for "<em>side, side, side</em>" and means that we have two triangles with all three sides equal.
If three sides of one triangle are equal to three sides of another triangle, the triangles are <em>congruent</em>.
Answer:265.25
Step-by-step explanation:
Given
Volume of box
height is 3 times the width
let height, length and breadth be H, L & B
4=B^2\times L[/tex]
Cost of side walls $
Cost of base $
Cost of side walls
Cost of base
Total cost
differentiate C w.r.t B to get minimum cost
L=2.19 m
C=$ 265.25
Answer:
To avoid expansion, you can just use the power of a power rule and multiply the two exponents from the start.
Step-by-step explanation:
(<em>x</em>^4)^3
= <em>x</em>^4×3
= <em>x</em>^12