The area shaded in green is 864 cm²
<h3>Similar figures</h3>
Similar figures, corresponding angles are congruent and the sides are ratio of each other. Therefore,
AB / PQ = CD / RS
30 / 10 = 24 / RS
30RS = 240
RS = 240 / 30
RS = 8 cm
let find the height of trapezium PQRS.
AB / PQ = 36 / h
30 / 10 = 36 / h
30h = 360
h = 360 / 30
h = 12 cm
Therefore,
area of the green portion = area of ABCD - area of PQRS
<h3>Area of a trapezium</h3>
Therefore,
area of ABCD = 1 / 2(24 + 30)36 = 1 / 2 (54)36 = 1944 / 2 = 972 cm²
area of PQRS = 1 / 2(10 + 8)12 = 1 / 2(18)12 = 216 / 2 = 108 cm²
Area of the green portion = 972 - 108 = 864 cm²
learn more on trapezium here: brainly.com/question/11961445
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In order to find any of the info we need we have to find the first derivative of the equation. If
, then
. We are told to find the slope at point (1, 7). Using that x value in our derivative will give us the slope of the line at that point. y' = -(1)^2+8. So y' = 7. That's the slope of the line. Now we will use that slope along with the x and y coordinate in the slope-intercept form of a line to solve for b. 7 = 7(1) + b so b = 0. Our equation then is y = 7x. If you graph these in the same window on your calculator, you can see how perfectly that align at the given point. It's really quite perfect.
If F(3) then 3=x. So all you would do is substitute 3 in for x
-3x+4y=-18
2x-y=7
the answer qould be C.(2,-3)
-3(2)+4(-3)=-18
-6+(-12)=-18
-18=-18
2(2)-(-3)=7
4+3=7
7=7
C.
