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1 year ago

Product of 3.24 0.45 x 0.72 0.45 x 72 4.5 x 0.7 4.5 x 7.2

Mathematics

2 answers:

Dvinal [7]1 year ago

7 0

4.5 * .72 is it so I’m guessing that was supposed to be C or D

natta225 [31]1 year ago

4 0

Answer:

4.5 x 0.72

Step-by-step explanation:

I AM ASSUMING THAT YOU FORGOT TO ADD 2 AFTER 0.7 IN 4.5 x 0.7

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Answer:

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Step-by-step explanation:

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2 years ago

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timama [110]

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2 years ago

Suppose in this semester, our Exam 1 average was about 86 with an SD of about 10. Suppose the correlation between our Exam 1 and

Oduvanchick [21]

Answer:

the slope of the regression equation for predicting our Exam 2 scores from Exam 1 scores is 0.492

And the y-intercept of the regression equation for predicting our Exam 2 scores from Exam 1 is 33.688

Step-by-step explanation:

Given the data in the question;

mean X" = 86

SD σx = 10

Y" = 76

SD σy = 8.2

r = 0.6

Here, Exam 2 is dependent and Exam 1 is independent.

The Regression equation is

y - Y" = r × σy/σx ( x - x" )

we substitute

y - 76 = 0.6 × 8.2/10 ( x - 86 )

y - 76 = 0.492( x - 86 )

y - 76 = 0.492x - 42.312

y = 0.492x - 42.312 + 76

y = 0.492x + 33.688

Hence, the slope of the regression equation for predicting our Exam 2 scores from Exam 1 scores is 0.492

And the y-intercept of the regression equation for predicting our Exam 2 scores from Exam 1 is 33.688

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2 years ago

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photoshop1234 [79]

$\displaystyle\int_{-3}^3|x+2|\,\mathrm dx$

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$|x|=\begin{cases}x&\text{for }x\ge0\\-x&\text{for }x$

So we can split up the integration interval at $x=-2$ and apply this definition to rewrite the integral as

$\displaystyle\int_{-3}^{-2}(-(x+2))\,\mathrm dx+\int_{-2}^3(x+2)\,\mathrm dx$
$=\displaystyle-\int_{-3}^{-2}(x+2)\,\mathrm dx+\int_{-2}^3(x+2)\,\mathrm dx$
$=-\left(\dfrac12x^2+2x\right)\bigg|_{x=-3}^{x=-2}+\left(\dfrac12x^2+2x\right)\bigg|_{x=-2}^{x=3}$
$=\dfrac12+\dfrac{25}2=13$

7 0

2 years ago