Step-by-step explanation:
Since it is a regular pentagon, all five sides are equal and you know one side is x-3. Thus the equation would be: x-3 = 18.8/5
x - 3 = 18.8/5
= 3.76
x = 3.76 + 3
x = 6.76
Answer:
<em>1 ) Adjacent angles,</em>
<em>2 ) See solution below</em>
Step-by-step explanation:
Question 1. Provided ∠ 1 and ∠ 1 are near one another, they can be referred to as adjacent ∠s;
<em>Solution; Adjacent angles</em>
Question 2.
Angles 5, and 6 are consecutively near one another, and thus are adjacent angles,
Angles 5 and 9 are supplementary knowing that they lie on a straight angle, so that they can be best named a linear pair, provided there are only two of these angles,
Angles 5 and 8 are opposite to one another so that they are ≅, thus should be names as vertical angles
<em>Solution; </em>
Angle | Adjacent Angles | Linear Pair | Vertical angles
∠ 5, 6 | Check! | |
∠ 5, 9 | | Check! |
∠ 5, 8 | | | Check!
Answer:
Step-by-step explanation:
Let y represent students in the class
55% of y = 78
0.55y= 78
y = 142
Hello :
all n in N ; n(n+1)(n+2) = 3a a in N or : <span>≡ 0 (mod 3)
1 ) n </span><span>≡ 0 ( mod 3)...(1)
n+1 </span>≡ 1 ( mod 3)...(2)
n+2 ≡ 2 ( mod 3)...(3)
by (1), (2), (3) : n(n+1)(n+2) ≡ 0×1×2 ( mod 3) : ≡ 0 (mod 3)
2) n ≡ 1 ( mod 3)...(1)
n+1 ≡ 2 ( mod 3)...(2)
n+2 ≡ 3 ( mod 3)...(3)
by (1), (2), (3) : n(n+1)(n+2) ≡ 1×2 × 3 ( mod 3) : ≡ 0 (mod 3) , 6≡ 0 (mod)
3) n ≡ 2 ( mod 3)...(1)
n+1 ≡ 3 ( mod 3)...(2)
n+2 ≡ 4 ( mod 3)...(3)
by (1), (2), (3) : n(n+1)(n+2) ≡ 2×3 × 4 ( mod 3) : ≡ 0 (mod 3) , 24≡ 0 (mod3)
Answer:
1. x=3
2. x=2
3. 0 i think
4. y=6
5. x=7/5
Bonus: k=6
Step-by-step explanation:
combine like terms