Since the sign is positive, the entropy increased by 88.48 J/K.
Examine the phases of the species present to determine whether a physical or chemical process will cause an increase or decrease in entropy. Keep in mind "Silly Little Goats" to aid you in telling.
[1 Sf K+1 + 1 Sf Br-1 (aq)] ([1Sf(KBr (s))])
[1(102.5) + 1(82.42)] - [1(96.44)] = 88.48 J/K
If the entropy has grown, we say that Delta S is positive, and if it has dropped, we say that Delta S is negative. Due to its ionic nature, KBr is soluble in water and causes the 'K(+)' ions to hydrate.
Learn more about Entropy here-
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1. C
2. C
3. In elastic deformation, the deformed body returns to its original shape and size after the stresses are gone. In ductile deformation, there is a permanent change in the shape and size but no fracturing occurs. In brittle deformation, the body fractures after the strength is above the limit.
4. Normal faults are faults where the hanging wall moves in a downward force based on the footwall; they are formed from tensional stresses and the stretching of the crust. Reverse faults are the opposite and the hanging wall moves in an upward force based on the footwall; they are formed by compressional stresses and the contraction of the crust. Thrust faults are low-angle reverse faults where the hanging wall moves in an upward force based on the footwall; they are formed in the same way as reverse faults. Last, Strike-slip faults are faults where the movement is parallel to the crust of the fault; they are caused by an immense shear stress.
I hope this helped! These are COMPLEX questions though! =D
Answer:
3-methylhexane
Explanation:
you start counting from the longest chain to determine the correct name
Answer:
Temperature stays constant.
Explanation:
During a phase change, the temperature does not change. Temperature will only change when a phase change is completed.
Answer:
17.78g
Explanation:
m/M = C×V
m/101.102= 0.7× 0.25
m= 101.102×0.7×0.25= 17.78g
