Answer:
D. d = sqrt( ( x2-x1)^2 + (y2-y1)^2)
C. d = sqrt( ( x1-x2)^2 + (y1-y2)^2)
B. d = sqrt( (|x2-x1|^2 + |y2-y1|^2)
Step-by-step explanation:
Given two points (x1, y1) and (x2,y2) we can find the distance using
d = sqrt( ( x2-x1)^2 + (y2-y1)^2)
The order of the terms inside the square doesn't matter
d = sqrt( ( x1-x2)^2 + (y1-y2)^2)
When we are squaring are term, we can take the absolute value before we square and it does not change the value
d = sqrt( (|x2-x1|^2 + |y2-y1|^2)
Answer:
Yes
Step-by-step explanation:
Yes, the given point makes the inequality true. We end up with a true statement.
Hope this helps.
Answer:
X=6
Step-by-step explanation:
5(x-1)+3x=7(x+1)
5x-5+3x=7x+1
8x-5=7x+1
8x-7x=1+5
X=6
So the answer is X=6
Plug 4 for x and solve.
y = -3/4 * 4 + 3
y = -12/4 + 3
y = -3 + 3
y = 0
So the missing coordinate is 0.
