Answer:
2
Step-by-step explanation:
The "average value of function f(x) on interval [a, b] is given by:
f(b) - f(a)
ave. value = ---------------
b - a
Here f(t)=(t-2)^2.
Thus, f(b) = (b - 2)^2. For b = 6, we get:
f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16
For a = 0, we get:
f(0) = (0 - 2)^2 = 4
Plugging these results into the ave. value function shown above, we get:
16 - 4
ave. value = ------------ = 12/6 = 2
6 - 0
The average value of the function f(t)=(t-2)^2 on [0,6] is 2.
1. 3y
multiplying 3 and y together gets 3y
2. y-5
5 less implies that we subtract 5 from y
3. y+7
adding 7 to y, self-explanatory
4. 9y
same thing as #1
5.
quotient of implies division, since number y is listed first, y is the numerator
Answer:
Step-by-step explanation:
Answer:
D (42,-56)
Step-by-step explanation:
Scale factor means you multiply, so you multiply (6,-8) by 7.
6 x 7 is 42 and 7 x -8 is -56. So your answer is D (42,-56).