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2 years ago

If x varies inversely as y and x = 24 when y = 4, find x when y = 12.

Mathematics

1 answer:

ANTONII [103]2 years ago

8 0

what that makes no sense

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The volume of a cone is 62.8 cubic inches. The height of the cone is 15 inches. What is the radius of the cone, rounded to the n

Salsk061 [2.6K]

Answer:

R = sqrt 3 * (V /( pi * h))

V = 62.8

pi = 3.14

h = 15

now we sub

R = sqrt 3 * (62.8 / (3.14 * 15)

R = sqrt 3 * (62.6 / 47.1)

R = sqrt 3 * 1.33

R = sqrt 3.99

R = 1.9 rounds to 2 inches <===

Step-by-step explanation:

4 0

2 years ago

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A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

8 0

2 years ago

Priya bought x grams of flour. Clare bought 3/8 more than that. Select one equation that represent the relationship between the

statuscvo [17]

Answer:

The relationship ship equation:

y = x + 3/8x

Step-by-step explanation:

Let 'x' be the grams of flour Priya bought

Let Clare bought 'y' grams of flour

As Clare bought 3/8 more than that.

y = x + 3/8x

Thus, the relationship ship equation:

y = x + 3/8x

3 0

2 years ago

P and a are both prime numbers. Find the values of p and q so that 6*54*p/q is a perfect cube.

daser333 [38]

6x54= 324

6x50=300

6x4=24

300+24=324

The previous nearest cube root is 216 and the next cube root would be 343.

p/q could be any prime number which there are a lot of.

im going to say p is 1 and q is 3

next you would divide 1 by 3

1/3=0.666666667

324x0.666666667=216 exact

3 0

2 years ago

What is the answer to the problem 6x+1+7x

My name is Ann [436]

Mmm should be 13x+1

5 0

2 years ago

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