The white Christmas tree is 7.55m
Green Christmas tree is twice as tall as white Christmas tree: 7.55 * 2 = 15.1m
High golden Christmas tree: 15.1m - 0.454m = 14.646m
The total height of 3 Christmas trees is: 7.55m + 15.1m + 14.646m = 37.296m
Choose: A 37.296m
Change 55% to 0.55
0.55 x 2900 = 1595
Answer: D. 0.9967
Step-by-step explanation: To solve this, you need to do the z-score formula with both numbers. So 30-22/2.5 = 3.2. On the z-score chart, that equals .9993. Hold onto that number. Then you do the same with 15. 15-22/2.5 = -2.8. On the z score chart, that equals .0026. Subtract those numbers. .9993 - .0026 = .9967. It's not as compacted as it looks <3
Answer: Angle ABC = 60, angle CBD = 120 and angle GFH = 60
Step-by-step explanation: Line ABD is parallel to line EFG. Line line CFH is a straight line that cuts across both parallel lines. Therefore, angle FBD and angle HFG are corresponding angles. That means angle FBD equals 3x. Also 3x plus 6X equals 180. That is,
3x + 6x = 180 {Sum of angles on a straight line equals 180}
9x = 180
Divide both sides of the equation by 9
x = 20.
That means angle 6x measures 6(20) and that is 120 degrees.
Also angle 3x measures 3(20) and that is 60 degrees.
Angle ABC + Angle CBD = 180 {Sum of angles on a straight line equals 180}
Angle ABC + 120 = 180
Angle ABC = 180 - 120
Angle ABC = 60
Also angle CBD equals 6x, and x = 20. Therefore angle CBD = 6 x 20
Angle CBD = 120.
And then, angle GFH = 3x, and x equals 20. Hence angle GFH = 60.
Therefore angle ABC = 60, angle CBD = 120 and angle GFH = 60.
Answer:
A. Minimum = 54, Q1= 69.5, Median = 75, Q3= 106, Maximum = 183
Step-by-step explanation:
Arranging the data set in order from least to greastest we get:
54, 68, 71, 72, 75, 84, 104, 108, 183
From this, we can see that the minimum value is 54 and the maximum value is 183.
Taking a number off one by one on each side of the data set gives the median. In the middle lies 75, so that is our median
To find quartile ranges, split the data set into two where the median lies, then, find the median of those two data sets. The medians will be the values of the upper (Q3) and lower quartiles (Q1).
Q1: 54, 68, 71, 72
68 + 71 = 139
139 ÷ 2 = 69.5
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Q3: 84, 104, 108, 183
104 + 108 = 212
212 ÷ 2 = 106
Option A is the only answer with all of these values, therefore, it is the answer.
hope this helps!
