Answer:
The APR will increase quite substantially
Explanation:
Answer: a. $73,810.88
b. $10,185.18
Explanation:
a. The payments of $11,000 are constant so this can be considered an Annuity.
The cost of the Computer is it's present value which is,
Present Value of Annuity = Annuity Payment * Present Value Interest Factor of Annuity, 11%, 10 periods
= 11,000 * 6.71008 (Payment is made at the end of the year so this is an Ordinary Annuity)
= $73,810.88
b. When an Annuity is instead paid at the beginning of the period it is considered to be an Annuity due.
The formula is the same but for the figures ,
Present Value of Annuity Due = Annuity * Present Value Interest Factor of an Annuity Due, 11% , 10 periods
73,810.88 = Annuity * 7.24689
Annuity = 73,810.88/7.24689
= $10,185.18
Answer:
limited problem solving
Explanation:
Limited problem solving -
It refers to the process of buying certain goods and services , when the person have only limited knowledge about the product , is referred to as limited problem solving .
People having lack of knowledge may even end up buying the wrong product .
Hence , from the given scenario of the question ,
The correct term is limited problem solving .
Answer:
$3,667.44
Explanation:
The amount you would be willing to pay today can be determined by finding the present value of the cash flows
Present value is the sum of discounted cash flows
Present value can be calculated using a financial calculator
Cash flow each year from year 1 to 4 = $25
Cash flow in year 5 = $25 + $5000
I = 7%
Present value = $3,667.44
To find the PV using a financial calculator:
1. Input the cash flow values by pressing the CF button. After inputting the value, press enter and the arrow facing a downward direction.
2. after inputting all the cash flows, press the NPV button, input the value for I, press enter and the arrow facing a downward direction.
3. Press compute
Answer:
a) 0.667
b) Yes
Explanation:
Data provided in the question:
Mean = 0.04
Standard Deviation = 0.003
Upper Specification Limit, USL = 0.046
Lower Specification Limit, LSL = 0.034
Now,
a) Capability Index is given as:
Cp =
or
Cp =
or
Cp = 0.667
Also,
Cpk = min(
or
Cpk = min(
or
Cpk = min( 0.667
, 0.667 )= 0.667
Since,
Cp and Cpk are same in this case
therefore, it is ideal condition and process is capable
b) yes