The balanced equation for the neutralisation reaction is as follows
2H₃PO₄ + 3Mg(OH)₂ --> Mg₃(PO₄)₂ + 6H₂O
stoichiometry of H₃PO₄ to H₂O is 2:6
number of H₃PO₄ moles reacted - 0.24 mol
if 2 mol of H₃PO₄ form 6 mol of H₂O
then 0.24 mol of H₃PO₄ forms - 6/2 x 0.24 = 0.72 mol of H₂O
therefore 0.72 mol of H₂O are formed
Answer:
110L
Explanation:
Boyle's Law states that P1×V1=P2×V2
Volume is indirectly proportional to Pressure so P×V is constant
P1=55atm
V1=6L
P2=3atm
V2 is to be found
P1×V1=P2×V2
6×55=3×V2
330=3×V2
Answer: V2=110L
Answer:
D. The presence of a base catalyst.
E. The presence of an acid catalyst. and
F. The presence of heat.
Explanation:
An electrolyte<span> is a substance that produces an electrically conducting solution when dissolved in a polar solvent, such as water. </span>
The percentage composition of CF4 is %C = 13.64% and %F = 86.36%
The solution are as follows:
Molar mass of CF4 = 88
<span>molar mass of C = 12 </span>
<span>molar mass of F = 4x19 = 76 </span>
<span>% C = 12/88 x 100 = 13.64% </span>
<span>% F = 76/88 x 100 = 86.36%</span>