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2 years ago

Put the following equation of a line into slope-intercept form, simplifying all

Mathematics

2 answers:

Fudgin [204]2 years ago

5 0

4y=5x+4
Divid by 4 to make slop intercept form
Y=5/4y +1
Slop =5/4

yKpoI14uk [10]2 years ago

3 0

Answer:

$\boxed {\boxed {\sf y= \frac{5}{4}x+1}}$

Step-by-step explanation:

We are given the equation of a line and asked to put it into slope-intercept form.

Slope-intercept form is:

$y=mx+b$

Where:

m= slope
b= y-intercept

In order to put the equation into slope-intercept form, we have to isolate the variable y by performing the inverse operation.

$5x-4y= -4$

5x is being added to -4y. The inverse of addition is subtraction, so subtract 5x from both sides of the equation.

$5x-5x-4y=-4-5x$

$-4y=-4-5x$

The variable y is being multiplied by -4. The inverse of multiplication is division. Divide both sides of the equation by -4.

$\frac {-4y}{-4}=\frac{-4-5x}{-4}$

$y= \frac{-4}{-4}+\frac{-5x}{-4}$

$y=1+\frac{5}{4}x$

Rearrange the equation.

$y= \frac{5}{4}x+1$

The fractions are completely simplified, so this is our final answer.

The equation of the line in slope-intercept form is $\bold {y= \frac{5}{4}x+1}}$ .

The slope is 5/4 and the y-intercept is 1.

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Which of the following equations describes the line shown below? Check all

Setler79 [48]

Answer:

y = -1/2 x + 2

Step-by-step explanation:

Which of the following equations describes the line shown below? Check all

that apply.

(-4, 4)

(2, 1)

The standard equation of a line is y = mx,+b

m is the slope

b is he y-inttercept

Get the slope

Slope m = y2-y1/x2-x1

Substitute the coordinate

M = 1-4/2-(-4)

M = -3/6

M = -1/2

Substitute m= -1/2 and (2,1) into y = mx+b

1 = -1/2(2)+b

1 = -1+b

b = 1+1

b=2

Get the equation

Recall y =mx+b

y = -1/2 x + 2

3 0

2 years ago

99.999 rounded to the nearest tenth would be?

ale4655 [162]

Answer:

Look at the place after the tenths, it is more than 5.

99.999

So add +1 to the tenths place.

Rounded to the nearest tenth would be:

4 0

2 years ago

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RES<br> Find (fºg)(1)<br> Ax) = x2 - 1<br> g(x)= v<br> a 0<br> c. 4.<br> b.<br> d. 18<br> Help pls

slava [35]

Answer:

Step-by-step explanation:

So we have the two functions:

$f(x)=x^2-1\\g(x)=\sqrt x$

And we want to find:

$(f\circ g)(1)$

This is the same as:

$f(g(1))$

So, to find the answer, find g(1) first:

$g(x)=\sqrt x\\g(1)=\sqrt1\\g(1)=1$

Now, substitute this value for g(1):

$f(g(1))\\=f(1)$

And plug this into f(x):

$f(x)=x^2-1\\f(1)=(1)^2-1\\f(1)=1-1=0$

Therefore:

$f(1)=f(g(1))=(f\circ g)(1)=0$

Our answer is A

3 0

2 years ago

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SOMEONE PLEASE HELP ME! I have a few of the explanations but I'm not sure if I need more please suggest some thank you

lesantik [10]

Answer:

For tingle #1

We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.

$C=180-(A+B)$

$C=180-(21.24+27.14)$

$C=131.62$

We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.

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In this one, we can find everything and there is one one value for each.

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Since we have a right triangle, we can find side c using the Pythagorean theorem

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