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2 years ago

Simple Question! Help!

Physics

2 answers:

Korvikt [17]2 years ago

8 0

60km/hr..

I think so....

Butoxors [25]2 years ago

3 0

<h3>Answer:</h3>

60 km/s

<h3>step-step wise explaination:</h3>

60 kilometers / 60 minutes

= 1 kilometer / minute

as we know to convert kilometer / min we should multiply 60 to speed value

therefore, (1×60/ 1) km/hr=60 km/ hr

if you want to know why 60 multiplied with it then read this

1 km/min to km/hr

1 minute = 1/60 hour

so, for converting minute to hour we multiply 1/60

when it goes to top then it multiplied

I know it's little complicated let see it by equation

1 km/min = (1 / 1×1/60) km/h

=(1 / 1/60) km/hr

= 60 km/hr

( note there is no change in km so it remains without multiplied)

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Three point charges are arranged on a line. Charge q3 = 5 nC and is at the origin. Charge q2 = - 3 nC and is at x = 4 cm. Charge

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q₁ = + 1.25 nC

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Theory of electrical forces

Because the particle q₃ is close to two other electrically charged particles, it will experience two electrical forces and the solution of the problem is of a vector nature.

Known data

q₃=5 nC

q₂=- 3 nC

d₁₃= 2 cm

d₂₃ = 4 cm

Graphic attached

The directions of the individual forces exerted by q1 and q₂ on q₃ are shown in the attached figure.

For the net force on q3 to be zero F₁₃ and F₂₃ must have the same magnitude and opposite direction, So, the charge q₁ must be positive(q₁+).

The force (F₁₃) of q₁ on q₃ is repulsive because the charges have equal signs ,then. F₁₃ is directed to the left (-x).

The force (F₂₃) of q₂ on q₃ is attractive because the charges have opposite signs. F₂₃ is directed to the right (+x)

Calculation of q1

F₁₃ = F₂₃