First, let's review what the "factorial operator" ! means.
5! = 5*4*3*2*1.
3! = 3*2*1
7! = 7*6*5*4*3*2*1
Then:
7! 7*6*5*4*3*2*1 7*6*5*4 5040
----- = ----------------------- = ------------- = ----------- = 5040 (answer)
3! 3*2*1 1 1
B.
<span>$5852.86
Working;
</span><span>A = P(1 + r)^t
A=5000(1+</span>
)^5
A=<span>5852.86</span>
Answer:
Step-by-step explanation:
x²+y²=r²
r²=12
r=√12=2√3
We have the following expression:
y = logbx
We clear x of the expression.
We have then:
b ^ y = b ^ (logbx)
Rewriting:
x = b ^ y
Substituting we have:
x = b ^ 0
x = 1
Answer:
If (x, 0) lies on the graph of y = logbx, then:
x = 1
Answer:
Evidently, without the calculating 5 1/5 times 2/5 would be larger than 5 1/5 since you are already gonna multiply 2/5 and that would make it larger.
Hope this helps!
Branliest would be appreciated :DD
Step-by-step explanation:
