Answer:
<h3>A-5N B-6N C-7N D-8N</h3>
Explanation:
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Answer : The pressure of the helium gas is, 1269.2 mmHg
Explanation :
To calculate the pressure of the gas we are using ideal gas equation:
where,
P = Pressure of 
gas = ?
V = Volume of gas = 210. mL = 0.210 L (1 L = 1000 mL)
n = number of moles = 0.0130 mole
R = Gas constant = 
T = Temperature of gas = 
Putting values in above equation, we get:
Conversion used : (1 atm = 760 mmHg)
Thus, the pressure of the helium gas is, 1269.2 mmHg
Answer:
0.2007 nm
3.57 cm
0.01478 g
8280000 pg
Explanation:
1)200.7 pm
1 picometer is equal to 0.001 nanometer.
1 nm = 1000 pm
200.7 pm× 1 nm / 1000 pm = 0.2007 nm
2)0.000357 hm
1 hectometer is equal to 10,000 centimeter.
1 hc = 10,000 cm
0.000357 hc× 10,000 cm / 1 hc = 3.57 cm
3) 14.78 mg
1 gram is equal to 1000 milligram.
1 g = 1000 mg
14.78 mg × 1 g/1000 mg = 0.01478 g
4)8.280 µg
1 microgram is equal to 10⁶ picogram.
1 µg = 1000000 pg
8.280 µg× 10⁶ pg/ 1µg = 8.280×10⁶ pg or 8280000 pg
Moles = 15.5 g / 40 g/mol = 0.3875 mol
M = 0.3875 mol / 0.250 L = 1.55M
We are given with a compound, Zinc (Zn) having a 1.7 x 10
^23 atoms. We are tasked to solve for it's corresponding mass in g. We need to
find first the molecular weight of Zinc, that is
Zn= 65.38 g/mol
Not that 1 mol=6.022x10^{23} atoms, hence,
1.7 x 10 ^23 atoms x 1 mol/6.022x10^{23} atoms x65.38
g/ 1mol
=18.456 g of Zn
Therefore, the mass of Zinc 18.456 g
