Correct Answer:Option A. 0.01
Solution:This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.
Converting 90 to z-score:
Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.
Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
Answer:
m∠CDE < m∠DEC < m∠ECD
OR
m∠D < m∠E < m∠C
Step-by-step explanation:
According to the angle-side inequalities theorem: In a triangle, the angle opposite to a longer side is larger, and vise versa, the side opposite to a larger angle is longer.
So, the order from smallest to largest is:
m∠CDE < m∠DEC < m∠ECD
OR
m∠D < m∠E < m∠C
Answer:
rounding to the nearest tenth
Step-by-step explanation:
The solution to your problem is as follows:
The tangent line passes through (4,-6), so x = 4 when y = -6
=> f(4) = -6
The tangent line will have a constant gradient.
gradient is m = (-6 - 9)/(4 - 10) => 5/2
Equation is y - 9 = (5/2)(x - 10)
=> y - 9 = (5/2)(x-10)
<span>i.e. y = (5/2)(x-10) + 9
</span> y = (5/2)x - 25 + 9 = y = (5/2)x - 16
Now, f '(x) = dy/dx = 5/2
so, f '(4) = 5/2....i.e. gradient is 5/2 whatever the value of x.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.