To ease your problem, consider "L" as you x-axis
Then the coordinate become:
A(- 4 , 3) and B(1 , 2) [you notice that just the y's changed]
This is a reflection problem.
Reflect point B across the river line "L" to get B', symmetric of B about L.
The coordinates of B'(1 , -1) [remember L is our new x-axis]
JOIN A to B' . AB' intersect L, say in H
We have to find the shortest way such that AH + HB = shortest.
But HB = HB' (symmetry about L) , then I can write instead of
AH + HB →→ AH + HB'. This is the shortest since the shortest distance between 2 points is the straight line and H is the point requiered
The awnser is 6(4t-3) I hope this helps u
Answer:
Step-by-step explanation:
First substitue the coordinates to the equation so
x=9, y=2
you would get
2=-3/7(9) + b
we put b because we are trying to find the new slope
multiply the two numbers above
2=-3/6/7 + b
subtract the whole number from both sides
b= 5/6/7
in equation would be
y= -3/7 + 5/6/7
Let me know if there is an error.
Answer:
-6
Step-by-step explanation:
3n = n² - 54
n² - 3n - 54 = 0
n² - 9n + 6n - 54 = 0
n(n - 9) + 6(n - 9) = 0
(n - 9)(n + 6) = 0
n = 9 , -6
Answer:
similar and congruent
Step-by-step explanation:
those are the only words i know
