Answer:
Step-by-step explanation:
Hint:
Answer:
Point of intersections are (0, -7) and (5, -2).
Step-by-step explanation:
From the graph attached,
A straight line is intersecting the circle at the two points (0, 7) and (5, -2).
Now solve algebraically,
Equation of the line → y = x - 7 -------(1)
Equation of the circle → (x - 5)² + (y + 7)² = 25 -------(2)
By substituting the value of y from equation (1) to equation (2)
(x - 5)² + (x - 7 + 7)² = 25
(x - 5)² + x² = 25
x² - 10x + 25 + x² = 25
2x² - 10x = 0
x² - 5x = 0
x(x - 5) = 0
x = 0, 5
From equation (1),
y = 0 - 7 = -7
y = 5 - 7 = -2
Therefore, point of intersections are (0, -7) and (5, -2).
Answer:
-1 12⁄13
Step-by-step explanation:
-13x = 25 [Divide by -13]
x = -1 12⁄13
13 is your <em>divisor</em>, which will be your denominator, and the numerator is your <em>remainder</em><em>.</em><em> </em>Since 13 goes into 25 ONCE, 1 gets multiplied by 13 to get 13, then deduct that from 25 to get your remainder of 12. This is where you start putting the pieces together as a mixed number. Then attach the negative because whenever you divide a positive by a negative, you get a negative:
-25⁄13 = -1 12⁄13
I am joyous to assist you anytime.
Divide both sides by 2 for the first one.
2c/2>2/2
c>1
simplify both sides for the second 1
1/6d>=1
6*(1/6d).=(6)*(1)
d>=6
For the last one
subtract 9 from both sides
r+9-9<=23-9 so that r<=14
Hope this helps!
Answer: 5:3, 5/3, 5 to 3
Step-by-step explanation: