Area of ∆=1/2bh
80yd^2=1/2(b)(10yd)
80yd^2=5yd(b)
80yd^2÷5yd=b
16yd=b
Answer:
x = 9
Step-by-step explanation:
Isolate x first by moving 16 to the other side
x = 25 - 16
x = 9
Answer:
Option b) is correct.
The completed factor of given expression is 
Step-by-step explanation:
Given expression is 
To find the completed factor for the given expression:
:
Taking the common number "2" outside to the above expression we get
Now rewritting the above expression as below
(since 16 can be written as the number 2 to the power of 4)
The above expression is of the form 
Here 
and 
Therefore it becomes
The above expression is of the form
Here 
and 
Therefore it becomes
Therefore
Option b) is correct.
The completed factor of given expression is
The length of the rectangle is 20 inches, and the width of the rectangle is 4 inches if the table runner has an area of 80 square inches. The length and width of the table runner are whole numbers. The length is 5 times greater than the width.
<h3>What is the area of the rectangle?</h3>
It is defined as the space occupied by the rectangle which is planner 2-dimensional geometry.
The formula for finding the area of a rectangle is given by:
Area of rectangle = length × width
The area of the table runner = 80 square inches
Let's assume the length of the rectangle is L and the width is W
Then L = 5×W ...(1)
L×W = 80 ...(2)
Put the value of L in the equation (2)
5W(W) = 80
5W² = 80
W² = 16
W = ±4
Width cannot be negative.
W = 4 inches putting this value in the equation (1)
L = 5(4) = 20 inches
Thus, the length of the rectangle is 20 inches, and the width of the rectangle is 4 inches if the table runner has an area of 80 square inches. The length and width of the table runner are whole numbers. The length is 5 times greater than the width.
Learn more about the area here:
brainly.com/question/14383947
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