Answer:
• No
• Yes
• Yes
• No
Step-by-step explanation:
To determine if the 4 given values of y are solutions to the inequality, start by solving the inequality. Solving an inequality is just like that of an equation, except that the direction of the sign changes when the inequality is divided by a negative number.
-2y +7≤ -5
Subtract 7 on both sides:
-2y≤ -5 -7
-2y≤ -12
Divide by -2 on both sides:
y≥ 6
This means that the solution can be 6 or greater than 6.
-10 and 3 are smaller than 6 and are not a solutions, while 7 and 6 satisfies the inequality and are therefore solutions.
_______
Alternatively, we can also substitute each value of y into the inequality and check if the value is less than or equal to -5.
Here's an example to check if -10 is a solution.
-2y +7≤ -5
When y= -10,
-2y +7
= -2(-10) +7
= 20 +7
= 27
Since 27 is greater than 5, it is <u>not</u> a solution to the inequality.
Answer: Perimeter = 40
Area = 204
Step-by-step explanation:
Perimeter is the sum of all the sides:
11 + 12 + 17 = 40
The area of a triangle is 1/2 base x height
1/2( 17 x 24)
1/2( 408) = 204
I think it’s how far an object travels from starting point to ending point.
Answer:
Step-by-step explanation:
1.
Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.
2.
Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.
3.
Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following (). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,
4.
The same method used to solve problem (3) can be applied to this problem.
Answer:
Is this a joke?
Step-by-step explanation: