A student collected the data shown in the table below during an experiment.

Chemistry

2 answers:

yuradex [85]2 years ago

6 0

Answer: A. An alcohol thermometer can measure the freezing point of a liquid that freezes at −80 °C.

Based on the data, which of the following conclusions can be made about the use of mercury and alcohol thermometers?

<u><em>A. An alcohol thermometer can measure the freezing point of a liquid that freezes at −80 °C</em></u>.

B. An alcohol thermometer can measure a wider range of temperatures in a laboratory.

C. An alcohol thermometer is more reliable to measure the temperature of a liquid in a beaker that is 80 °C.

D. An alcohol thermometer is better to measure the boiling points of colorless liquids.

Explanation:

I just took the test and the correct answer is A. An alcohol thermometer can measure the freezing point of a liquid that freezes at −80 °C!

Good Luck!!

yanalaym [24]2 years ago

4 0

Answer:

An alcohol thermometer can measure the freezing point of a liquid that freezes at −80 °C.

Explanation:

A thermometer is a device used to measure temperature. A thermometer must contain a thermometric substance. A thermometric substance is any substance having a particular physical property that changes with temperature.

For all liquid-in-glass thermometers, the property that changes with change in temperature is the height of the liquid. There are two kinds of liquid-in-glass thermometers; mercury-in-glass thermometer and alcohol-in-glass thermometer.

Alcohol-in-glass thermometer measures very low temperatures up to as low as -115°C. If it measures such a low temperature, then it can efficiently measure -80°C hence the answer.

Alcohol-in-glass thermometers have a narrower temperature range than mercury-in-glass thermometer. The later is well adapter for the measurement bof higher tempetures up to 357°C.

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What change in volume results if 60 mL of a gas is cooled from 33 C to 5 C?

Eva8 [605]

Answer:

Change in volume on changing temperature from 33 $^{\circ}C$ to 5 $^{\circ}C$ is 5.49 mL

Explanation:

Initial volume of gas = V = 60 mL

Assuming final volume of gas to be V' mL

Initial temperature = T = 33 $^{\circ}C$ = 306 K

Final temperature = T' = 5 $^{\circ}C$ = 278 K

The relationship between volume and temperature of gas at constant pressure is shown below

$\displaystyle \frac{V}{V'}=\displaystyle \frac{T}{T'} \\\displaystyle \frac{60\textrm{ mL}}{V'} = \displaystyle \frac{306\textrm{ K}}{T} \\V' = 54.51 \textrm{ mL} \\\textrm{Change in volume} = \left ( V-V' \right ) \\\textrm{Change in volume} = \left ( 60-54.51 \right )\textrm{ mL} \\\textrm{Change in volume} = 5.49 \textrm{ mL}$

Change in volume on changing temperature = 5.49 mL

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Assoli18 [71]

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