The information that the nurse should include in the teaching is: D. The risk for developing DKA may be increased with the use of an insulin pump
Diabetes mellitus occur when a patient body does not produce insulin that is needed by the body leading to increase in the patient blood sugar level.
Insulin pump is a pump which are use when treating diabetes patients as it help to administer Insulin into the patient body when performing insulin therapy.
DKA which fully meaning is Diabetic ketoacidosis occur when a patient body does not have enough insulin leading to what is called ketones.
The risk for developing Diabetic ketoacidosis can be increased when a patient make use of insulin pump due to the following:
•When the pump fails to function normally due to low battery.
•When their is no longer insulin in the pump.
Inconclusion the information that the nurse should include in the teaching is: D. The risk for developing DKA may be increased with the use of an insulin pump.
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Answer:
Cells that support viral replication are called permissive. Infections of permissive cells are usually productive because infectious progeny virus is produced. Most productive infections are called cytocidal (cytolytic) because they kill the host cell. Infections of nonpermissive cells yield no infectious progeny virus and are called abortive. When the complete repertoire of virus genes necessary for virus replication is not transcribed and translated into functional products the infection is referred to as restrictive. In persistent and in some transforming infections, viral nucleic acid may remain in specific host cells indefinitely; progeny virus may or may not be produced.
Explanation:
Hope this helps! :)
Answer:
Appropriate Question:-
The output for a 60kg woman who runs up a 3m high flight of stairs in 3.5 sec.starting from rest but having a final speed of 2 m/s.
Given:-
Mass of woman=m=60kg.
Height=h=3m
Time=t=3.5secs.
To find :-
Here we want to calculate the output for a woman
Here first we should calculate work done first.
work \: done = mghworkdone=mgh
Applying the values,
work \: done = 10 \times 60 \times 3workdone=10×60×3
Work done= 1800Joule.
Now , lets calculate power,
power = \frac{workdone}{time \: taken} power=
timetaken
workdone
Now,
Applying the values ,
power = \frac{1800}{3.5} power=
3.5
1800
Power =514.2857 watt.
Hope it helps u mate .
Thank you .
Answer:
it's A! (I'm sorry but I don't feel like explaining why BTW lol)
