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2 years ago

9

7x+7+2z+9= please help me

1 answer:

fiasKO [112]2 years ago

8 0

Answer:

7x+2z+16

Step-by-step explanation:

find like terms

7 9

add them

7+9=16

7x+2z+16

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SOMEONE HELP ME IM FREAKING OUT I LITERALLY CANT WITH THIS QUESTION IM PRAYING PLEASE HELP ME IM SO SERIOUS IM GONNA END IT PLS

antiseptic1488 [7]

Answer:

$\sf -11+7\sqrt{2}$

Step-by-step explanation:

Given expression:

$\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }$

Rewrite 32 as 16 · 2:

$\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }$

Apply radical rule $\sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}$

$\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }$

As $\sf \sqrt{16}=4$ :

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }$

Multiply by the conjugate:

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }$

$\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}$

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4\sqrt{2}\sqrt{2}}{1-\sqrt{2}+\sqrt{2}-\sqrt{2}\sqrt{2}}$

As $\sf \sqrt{2}\sqrt{2}=\sqrt{4}=2$ :

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}$

$\sf \implies \dfrac{3-7\sqrt{2}+8}{1-2}$

$\sf \implies \dfrac{11-7\sqrt{2}}{-1}$

$\sf \implies -11+7\sqrt{2}$

7 0

1 year ago

Which is the rationalized form of the expression. A, B , C, or D?

grin007 [14]

Answer:

C

Step-by-step explanation:

Multiply the top and bottom, both by sqrtx-sqrt5. This is in order to rationalize the denominators.

You get answer C.

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2 years ago

Find the area of a circle with a diameter of 4.

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area of circle =22/7×4=12.56

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2 years ago

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Answer:

The equation is 10x = 300.

Step-by-step explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>

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2 years ago

Find each measurement indicated round your answers to the nearest tenth. Part 1d. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW

valkas [14]

Answer:

see explanation

Step-by-step explanation:

Using the Sine rule in all 3 questions

(1)

$\frac{a}{sinA}$ = $\frac{b}{sinB}$ , substitute values , firstly calculating ∠ B

[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]

$\frac{a}{sin78}$ = $\frac{18}{sin53}$ ( cross- multiply )

a sin53° = 18 sin78° ( divide both sides by sin53° )

a = $\frac{18sin78}{sin53}$ ≈ 22.0 ( to the nearest tenth )

(3)

$\frac{c}{sinC}$ = $\frac{a}{sinA}$ , substitute values

$\frac{35}{sinC}$ = $\frac{45}{sin134}$ ( cross- multiply )

45 sinC = 35 sin134° ( divide both sides by 35 )

sinC = $\frac{35sin134}{45}$ , then

∠ C = $sin^{-1}$ ( $\frac{35sin134}{45}$ ) ≈ 34.0° ( to the nearest tenth )

(5)

Calculate the measure of ∠ B

∠ B = 180° - (38 + 92)° = 180° - 130° = 50°

$\frac{a}{sinA}$ = $\frac{b}{sinB}$ , substitute values

$\frac{BC}{sin38}$ = $\frac{10}{sin50}$ ( cross- multiply )

BC sin50° = 10 sin38° ( divide both sides by sin50° )

BC = $\frac{10sin38}{sin50}$ ≈ 8.0 ( to the nearest tenth )

3 0

2 years ago