All points that lie in a given line with a defined equation, they satisfy the equation such that when the values of x and y are substituted they satisfy the given equation.
Substituting values of y and x in the equation y = 14x +4
(8,6), (-8,-5), (-16,0), (-20,1) doesn't satisfy the equation.
therefore in this case there is no point that would lie in the line
Two squares are congruent if they have the same side length.
in this problem what you are really looking for is which of these sets is a pathagorean triple. That means it will solve the pathagorean theorem. (a sqaured + b squared = c squared) c is always going to be the largest number or the hypotenuse. if you plug all the number sets into the theorem, only one works and that is 7, 24, 25 which is your answer.
Answer:
see explanation
Step-by-step explanation:
let pq = x
given oq - pq = 1 then oq = 1 + x
Using Pythagoras' identity, then
(oq)² = 7² + x²
(1 + x)² = 49 + x² ( expand left side )
1 + 2x + x² = 49 + x² ( subtract 1 from both sides )
2x + x² = 48 + x² ( subtract x² from both sides )
2x = 48 ( divide both sides by 2 )
x = 24 ⇒ pq = 24
and oq = 1 + x = 1 + 24 = 25 ← hypotenuse
sinq = 
= 
cosq = 
= 
Answer:
solo suma todos los valores x+4(3)+(x+x)
en el segundo x+5(2)+x+3(2)
en el tercero x-3+(2x+5)+(2x+5)
y en el cuarto x(3)+(x+4)
