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2 years ago

What is the common differenice for this arithmetic sequence?

Mathematics

2 answers:

yaroslaw [1]2 years ago

8 0

Answer:

The answer is D.

Step-by-step explanation:

The difference between each term is 4.

-2 - (-6) = 4

2 - (-2) = 4

6 - 2 = 4

10 - 6 = 4

Yuki888 [10]2 years ago

5 0

d. 4

here, -2-(-6)= -2+6=4

2-(-2)= 2+2=4

6- 2 = 4

10-6 = 4

so the common difference of them is 4.

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Example 1

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2 years ago

Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and x + 7y = 8

goblinko [34]

$\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y = \frac{17}{14} } \atop {x+7y=8}} \right.$

To solve this system by substitution, first isolate x in the second equation.

$x+7y=8$
$x+7y-7y=8-7y$
$x=8-7y$

Now, plug this expression ( $8-7y$ ) for x in the top equation to solve for y.

$\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}$
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Now that you have y, plug it into the second equation and solve for x.

$x+7y=8$
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$x=1$

Last step is to plug your x- and y-values in to both equations to check your work.

$\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}$

$\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ; \frac{1}{3} * \frac{8}{8} = \frac{8}{24}$

$\frac{9}{24} + \frac{8}{24} = \frac{17}{24}$ <--True

$1+7(1)=8$
$1+7=8$ <--True

Answer:
$x=1 \\ y=1$

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2 years ago

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Evgen [1.6K]

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2 years ago

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Answer:

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